ISA Interchange

Welcome to the official blog of the International Society of Automation (ISA).

This blog covers numerous topics on industrial automation such as operations & management, continuous & batch processing, connectivity, manufacturing & machine control, and Industry 4.0.

All Posts

AutoQuiz: What is “Slip” in an AC Induction Motor?

 

AutoQuiz is edited by Joel Don, ISA's social media community manager.

 

This automation industry quiz question comes from the ISA Certified Automation Professional (CAP) certification program. ISA CAP certification provides a non-biased, third-party, objective assessment and confirmation of an automation professional's skills. The CAP exam is focused on direction, definition, design, development/application, deployment, documentation, and support of systems, software, and equipment used in control systems, manufacturing information systems, systems integration, and operational consulting. Click this link for more information about the CAP program.

 

“Slip” in an AC induction motor is defined as:

a) synchronous speed minus no load speed
b) difference between speed of stator field and rotor speed
c) rated speed plus synchronous speed
d) speed at which motor develops torque
e) none of the above

 

Slip is usually expressed as a percentage, and varies by motor, from nominally 0.5 percent for very large motors to about 5 percent for small, specialized motors.  If ns is the stator electrical speed and nr is the rotor's mechanical speed, the slip, S, is defined by:

S = (ns - nr) / ns

Motor rotation is developed in an AC induction motor through the effects of a moving magnetic field. As the speed of the rotor drops below the stator speed, or synchronous speed, the rotation rate of the magnetic field in the rotor increases, inducing more current in the rotor's windings and creating more torque.

Slip is required to produce torque. Under load, the rotor speed drops, and the slip increases enough to create sufficient additional torque to turn the load. A very efficient way to control slip is to use a variable frequency drive

The correct answer is B, "difference between speed of stator field and rotor speed.”

ReferenceNicholas Sands, P.E., CAP and Ian Verhappen, P.Eng., CAP.A Guide to the Automation Body of Knowledge. To read a brief Q&A with the authors, plus download a free 116-page excerpt from the book, click this link.

 

About the Editor
Joel Don is the community manager for ISA and is an independent content marketing, social media and public relations consultant. Prior to his work in marketing and PR, Joel served as an editor for regional newspapers and national magazines throughout the U.S. He earned a master's degree from the Medill School at Northwestern University with a focus on science, engineering and biomedical marketing communications, and a bachelor of science degree from UC San Diego.

 

Connect with Joel
LinkedInTwitterEmail

 

 

Joel Don
Joel Don
Joel Don is an independent content marketing, social media and public relations consultant. Prior to his work in marketing and PR, Joel served as an editor for regional newspapers and national magazines throughout the U.S. He earned a master's degree from the Medill School at Northwestern University with a focus on science, engineering and biomedical marketing communications, and a bachelor of science degree from UC San Diego.

Related Posts

ISA-95 and IIoT: Power is Nothing Without Control

The Internet, Internet of Things (IoT), and the Industrial Internet of Things (IIoT). Many different term...
David Jimenez Jun 18, 2021 5:30:00 AM

ISAGCA Proudly Announce the Top 20 Secure PLC Coding Practices

Over on our ISAGCA Blog, Sarah Fluchs has written an article outlining the background and thought process...
Steven Aliano Jun 15, 2021 12:00:00 PM

The New Normal

“In the rush to return to normal, use this time to consider which parts of normal are worth rushing back ...
Steve Mustard, ISA President Jun 15, 2021 5:30:00 AM